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Home»MAT»Alligation or Mixture Aptitude Questions and Answers (Solved MCQs)
MAT

Alligation or Mixture Aptitude Questions and Answers (Solved MCQs)

Updated:February 22, 20269 Mins Read

Here we are with another aptitude test for competitive exams. We have a collection of 36 Alligation & Mixture questions for practice. You’ll learn how to balance mixtures like a chef(with math skills), not a guesser. The set covers mixing ratios, dilution, and weighted average logic. Each question has an answer for quick self-check.

In addition we have have lot of other aptitude question and answers. You might want to check out that too.

36 Alligation or Mixture Aptitude Questions and Answers (Solved MCQs)

Alligation / Mixture Test: Basic Alligation (Ratio-first) (12 Challenging MCQ Questions)

Question 1. In what ratio should sugar at ₹30/kg be mixed with sugar at ₹50/kg to get a mixture worth ₹42/kg?

a) 1:2
b) 2:3
c) 3:2
d) 5:2

Answer:

b) 2:3 — Cheaper:dearer = (50−42):(42−30).

Question 2. In what ratio should 4% milk be mixed with 10% milk to get 7% milk?

a) 1:2
b) 2:1
c) 1:1
d) 3:2

Answer:

c) 1:1 — Equal deviations from 7%.

Question 3. In what ratio should 20% acid be mixed with 50% acid to get 35% acid?

a) 1:2
b) 2:1
c) 1:1
d) 3:2

Answer:

c) 1:1

Question 4. Tea at ₹200/kg is mixed with tea at ₹320/kg. In what ratio should they be mixed to get ₹260/kg?

a) 2:1
b) 1:2
c) 1:1
d) 3:2

Answer:

c) 1:1 — Deviations are equal (60 and 60).

Question 5. In what ratio should a 5% solution be mixed with a 20% solution to get an 11% solution?

a) 2:3
b) 3:2
c) 4:3
d) 5:4

Answer:

b) 3:2 — (20−11):(11−5) = 9:6.

Question 6. A mixture contains liquids in ratio 3:5. If their prices are ₹18/L and ₹42/L, find mean price per litre.

a) ₹30
b) ₹33
c) ₹36
d) ₹39

Answer:

b) ₹33 — Weighted mean = (3×18 + 5×42)/8.

Question 7. A mixture contains oils in ratio 7:3. If prices are ₹80/L and ₹140/L, find mean price per litre.

a) ₹92
b) ₹98
c) ₹104
d) ₹110

Answer:

b) ₹98

Question 8. How many litres of 15% solution must be added to 40 L of 30% solution to make it 25%?

a) 10 L
b) 15 L
c) 20 L
d) 25 L

Answer:

c) 20 L — Balance solute: 12 + 0.15x = 0.25(40+x).

Question 9. In what ratio should rice at ₹28/kg be mixed with rice at ₹35/kg to get ₹32.20/kg?

a) 3:2
b) 2:3
c) 4:3
d) 5:2

Answer:

b) 2:3 — (35−32.2):(32.2−28) = 2.8:4.2.

Question 10. A 12% solution is mixed with a b% solution in ratio 5:3 to get 18%. Find b.

a) 24%
b) 26%
c) 28%
d) 30%

Answer:

c) 28% — (5×12 + 3b)/8 = 18.

Question 11. In what ratio should 92-octane petrol be mixed with 98-octane petrol to get 95-octane petrol?

a) 1:3
b) 2:1
c) 1:1
d) 3:2

Answer:

c) 1:1 — Deviations are equal (3 and 3).

Question 12. In what ratio should 1/3 pure alcohol be mixed with 3/4 pure alcohol to get 60% alcohol?

a) 16:9
b) 9:16
c) 3:5
d) 5:3

Answer:

b) 9:16 — (45−36):(36−20) using /60 equivalents.

Alligation / Mixture Test: Replacement & Repeated Mixing (12 Challenging MCQ Questions)

Question 1. A 30 L vessel is full of milk. 6 L is removed and replaced with water (once). What is the percentage of milk now?

a) 70%
b) 75%
c) 80%
d) 84%

Answer:

c) 80% — Milk left = 30×(24/30).

Question 2. A 20 L vessel is full of milk. 5 L is removed and replaced with water, repeated 3 times. What % of milk remains?

a) 31.64%
b) 42.19%
c) 52.00%
d) 57.81%

Answer:

b) 42.19% — Fraction left = (15/20)³ = 27/64.

Question 3. A 25 L vessel is full of wine. 5 L is removed and replaced with water, repeated twice. How much wine remains?

a) 12.8 L
b) 14.4 L
c) 16 L
d) 18 L

Answer:

c) 16 L — Wine left = 25×(20/25)².

Question 4. A 40 L solution contains 25% acid. 10 L is removed and replaced with water (once). What is new acid %?

a) 12.5%
b) 15%
c) 18.75%
d) 20%

Answer:

c) 18.75% — Acid retained = 0.75 of original.

Question 5. A 40 L solution contains 25% acid. 10 L is removed and replaced with water, repeated twice. What is new acid %?

a) 12.5%
b) 14.0625%
c) 16.25%
d) 18.75%

Answer:

b) 14.0625% — Acid fraction = (30/40)².

Question 6. A 50 L salt solution is 10% salt. 5 L is removed and replaced with water, repeated 4 times. Find final salt %.

a) 5.61%
b) 6.56%
c) 7.29%
d) 8.10%

Answer:

b) 6.56% — Fraction left = (45/50)⁴ = 0.6561.

Question 7. A 30 L vessel is full of juice. x L is removed and replaced with water once. Now juice is 20%. Find x.

a) 18 L
b) 20 L
c) 24 L
d) 26 L

Answer:

c) 24 L — (30−x)/30 = 0.20.

Question 8. An 18 L vessel is full of alcohol. 3 L is removed and replaced with water, repeated twice. How much alcohol remains?

a) 10.0 L
b) 11.5 L
c) 12.5 L
d) 13.5 L

Answer:

c) 12.5 L — Alcohol left = 18×(15/18)².

Question 9. A 60 L mixture contains 75% milk. 12 L is removed and replaced with water once. What is new milk %?

a) 50%
b) 55%
c) 60%
d) 65%

Answer:

c) 60% — Milk retained factor = 48/60.

Question 10. A 20 L tank has 30% acid. 4 L is removed and replaced with water, repeated twice. Find final acid %.

a) 16.8%
b) 18.0%
c) 19.2%
d) 21.0%

Answer:

c) 19.2% — Acid fraction = (16/20)².

Question 11. A 32 L solution contains 40% alcohol. 8 L is removed and replaced with water, repeated 3 times. Find final alcohol %.

a) 12.5%
b) 15.0%
c) 16.875%
d) 18.0%

Answer:

c) 16.875% — Fraction left = (24/32)³.

Question 12. A 40 L vessel is full of milk. x L is removed and replaced with water, repeated twice. Now milk is 25%. Find x.

a) 10 L
b) 15 L
c) 20 L
d) 25 L

Answer:

c) 20 L — (1−x/40)² = 0.25.

Alligation / Mixture Test: Advanced Mixture Systems (3+ Components + Constraints) (12 Challenging MCQ Questions)

Question 1. 10 L of 20% acid, 15 L of 50% acid, and 25 L water are mixed. Find final acid %.

a) 16%
b) 18%
c) 19%
d) 21%

Answer:

c) 19% — Acid = 2 + 7.5 out of 50 L.

Question 2. Blend A: 40 L at 30% sugar. Blend B: 60 L at 20% sugar. If mixed, find final sugar %.

a) 22%
b) 24%
c) 25%
d) 26%

Answer:

b) 24% — Weighted mean of concentrations.

Question 3. Make 60 L oil at ₹84/L using ₹72/L and ₹96/L oils. How many litres of each are needed?

a) 20 L and 40 L
b) 30 L and 30 L
c) 40 L and 20 L
d) 45 L and 15 L

Answer:

b) 30 L and 30 L — Ratio 1:1 by alligation.

Question 4. Rice at ₹24, ₹30, ₹42 are mixed in ratio 2:3:1. Find mean price per kg.

a) ₹28
b) ₹30
c) ₹32
d) ₹34

Answer:

b) ₹30 — (2×24 + 3×30 + 1×42)/6.

Question 5. You must prepare 50 L of 26% acid using 40 L of 20% acid and 10 L of 50% acid. Is it possible?

a) No, it becomes 24%
b) No, it becomes 25%
c) Yes, it becomes 26%
d) Yes, it becomes 28%

Answer:

c) Yes, it becomes 26% — Acid = 8 + 5 = 13 in 50.

Question 6. Alloy X: 25 kg with 60% copper. Alloy Y: x kg with 80% copper. Find x to get 70% copper overall.

a) 15 kg
b) 20 kg
c) 25 kg
d) 30 kg

Answer:

c) 25 kg — Balance copper: 15+0.8x = 0.7(25+x).

Question 7. Coffee at ₹480/kg and ₹660/kg is mixed and sold at ₹690/kg with 15% profit. Find mixing ratio (₹480 : ₹660).

a) 1:1
b) 1:2
c) 2:1
d) 3:2

Answer:

b) 1:2 — CP = 690/1.15 = 600; ratio (660−600):(600−480).

Question 8. 12 L of 10% solution and 8 L of 25% solution are mixed. How many litres of 40% solution must be added to make the final mixture 25%?

a) 8 L
b) 10 L
c) 12 L
d) 14 L

Answer:

c) 12 L — 3.2+0.4x = 0.25(20+x).

Question 9. Make 45 kg alloy at 30% tin using 20% and 50% tin alloys. Find quantities of 20% and 50% alloys.

a) 15 kg and 30 kg
b) 20 kg and 25 kg
c) 30 kg and 15 kg
d) 33 kg and 12 kg

Answer:

c) 30 kg and 15 kg — Ratio (50−30):(30−20) = 2:1.

Question 10. Pulses at ₹80/kg and ₹110/kg are mixed in ratio 3:2. Find selling price per kg for 10% profit.

a) ₹99.2
b) ₹101.2
c) ₹103.4
d) ₹105.0

Answer:

b) ₹101.2 — CP = 92; SP = 92×1.10.

Question 11. Prepare 50 L of 30% acid using 20% and 40% acids, but 40% acid is limited to 15 L. Find quantities of 20% and 40% acids.

a) 25 L and 25 L
b) 30 L and 20 L
c) 35 L and 15 L
d) 40 L and 10 L

Answer:

c) 35 L and 15 L — With 15 L fixed; solve for remaining.

Question 12. Mixture A has sugar:water = 3:2 and Mixture B has sugar:water = 5:3. If 16 L of A is mixed with x L of B to make 61% sugar, find x.

a) 8 L
b) 10 2/3 L
c) 12 L
d) 14 L

Answer:

b) 10 2/3 L — 0.6×16 + 0.625x = 0.61(16+x).

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Amit
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Amit, a BE in Mechanical Engineering, is a math enthusiast dedicated to making math fun and accessible for kids in classes 1 to 10. With a knack for simplifying complex concepts, Amit offers easy-to-understand solutions, fostering a love for math in young minds across India.

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