Welcome to a set of challenging math riddles which will help in improving your problem-solving skills. The puzzles will help you stretch your thinking also help you in sharpening your approach towards numbers in creative ways. Some of the questions will require logical reasoning, and the others might have you solving equations or recognizing patterns. Take your time, think critically, and enjoy solving these brain teasers. Ready to dive in? Let’s get started!
Class 6 Math Riddles to Boost Math Skills with Answer
Question 1: I am a three-digit number. My tens digit is five more than my ones digit. My hundreds digit is eight less than my tens digit. What number am I?
Answer: The number is 194.
Explanation:
Let’s break down the clues:
- “My tens digit is five more than my ones digit.”
This means that the tens digit is 5 greater than the ones digit. Let the ones digit be x, so the tens digit will be x + 5. - “My hundreds digit is eight less than my tens digit.”
This means the hundreds digit is 8 less than the tens digit. If the tens digit is x + 5, the hundreds digit will be (x + 5) – 8 = x – 3.
Now, we know:
- The hundreds digit must be a number between 0 and 9, so x – 3 must be between 0 and 9.
- This means x must be at least 3 (because 3 – 3 = 0) and at most 9 (because 9 – 3 = 6).
Let’s test the possible values for x:
- If x = 4, then:
- The ones digit is 4.
- The tens digit is 4 + 5 = 9.
- The hundreds digit is 9 – 8 = 1.
So, the number is 194, which satisfies all the conditions.
Thus, the answer is 194!
Question 2: I am an odd number. Take away one letter, and I become even. What number am I?
Answer: The number is 7.
Explanation:
The word “seven” is an odd number, but if you take away the “s”, you are left with the word “even”, which is even.
Thus, the answer is 7!
Question 3: I am a two-digit number. The sum of my digits is 12. If you reverse my digits, I become 3 times my original number. What number am I?
Answer: The number is 36.
Explanation:
Let the tens digit be x and the ones digit be y. So, the number is 10x + y.
The sum of the digits is 12, so x + y = 12.
Reversing the digits gives the number 10y + x, and we are told that 10y + x = 3(10x + y).
By solving these equations, we get x = 3 and y = 9, so the number is 36.
Thus, the answer is 36!
Question 4: What number comes next in the sequence: 1, 4, 9, 16, ?
Answer: The next number is 25.
Explanation:
The sequence follows the pattern of square numbers: 1², 2², 3², 4², so the next number is 5² = 25.
Thus, the answer is 25!
Question 5: I am a number between 50 and 100. I am divisible by 6, and when divided by 6, the result is a two-digit number. What number am I?
Answer: The number is 60.
Explanation:
We know the number is divisible by 6 and lies between 50 and 100.
So, we check the multiples of 6: 54, 60, 66, 72, 78, 84, 90, 96. The only one that results in a two-digit number when divided by 6 is 60.
Thus, the answer is 60!
Question 6: What is the next number in the sequence: 2, 6, 12, 20, ?
Answer: The next number is 30.
Explanation:
The pattern is increasing by consecutive even numbers: 2 + 4 = 6, 6 + 6 = 12, 12 + 8 = 20, and 20 + 10 = 30.
Thus, the answer is 30!
Question 7: I am a three-digit number. My tens digit is half of my hundreds digit, and my ones digit is half of my tens digit. What number am I?
Answer: The number is 252.
Explanation:
Let the hundreds digit be x, the tens digit will be x/2, and the ones digit will be x/4.
When x = 8, the tens digit becomes 4, and the ones digit becomes 2.
Thus, the number is 252.
Thus, the answer is 252!
Question 8: What number am I? I am a two-digit number. My tens digit is one less than my ones digit, and the sum of my digits is 10.
Answer: The number is 19.
Explanation:
Let the tens digit be x and the ones digit be y. We are given that x + y = 10 and x = y – 1x = y – 1 into the equation x + y = 10, we get (y – 1) + y = 10, which simplifies to 2y – 1 = 10.
Solving for y, we get y = 5, and x = 419.
Thus, the answer is 19!
Question 9: I am a three-digit number. My hundreds digit is twice my tens digit, and my ones digit is one less than my tens digit. What number am I?
Answer: The number is 241.
Explanation:
Let the tens digit be x. The hundreds digit is 2x, and the ones digit is x – 1.
If x = 4, then the hundreds digit is 8, the tens digit is 4, and the ones digit is 3, so the number is 241.
Thus, the answer is 241!
Question 10: I am a two-digit number. My tens digit is three times my ones digit, and the sum of my digits is 12. What number am I?
Answer: The number is 48.
Explanation:
Let the ones digit be x and the tens digit be 3x.
The sum of the digits is 12, so 3x + x = 12.
Solving for x, we get x = 3, so the tens digit is 9 and the number is 48.
Thus, the answer is 48!
Question 11: What is the next number in the sequence: 3, 9, 27, 81, ?
Answer: The next number is 243.
Explanation:
The pattern is multiplying by 3: 3 × 3 = 9, 9 × 3 = 27, 27 × 3 = 81, and 81 × 3 = 243.
Thus, the answer is 243!
Question 12: What is the next number in the sequence: 5, 10, 15, 20, ?
Answer: The next number is 25.
Explanation:
The pattern is increasing by 5 each time: 5 + 5 = 10, 10 + 5 = 15, 15 + 5 = 20, and 20 + 5 = 25.
Thus, the answer is 25!
Question 13: I am a number. If you multiply me by 3, then subtract 6, the result is 18. What number am I?
Answer: The number is 8.
Explanation:
Let the number be x. We are told that 3x – 6 = 18.
Solving for x, we get x = 8.
Thus, the answer is 8!
Question 14: I am a two-digit number. The difference between my digits is 4. The sum of my digits is 10. What number am I?
Answer: The number is 64.
Explanation:
Let the tens digit be x and the ones digit be y. We know x – y = 4 and x + y = 10.
Solving these equations, we get x = 7 and y = 3, so the number is 64.
Thus, the answer is 64!
Question 15: I am a number. I am divisible by 2, 3, and 5. What number am I?
Answer: The number is 30.
Explanation:
The number is divisible by 2, 3, and 5. The smallest number that is divisible by all three is 30.
Thus, the answer is 30!
Question 16: I am a three-digit number. My tens digit is one less than my hundreds digit, and my ones digit is double my tens digit. What number am I?
Answer: The number is 194.
Explanation:
Let the hundreds digit be x, the tens digit will be x – 1, and the ones digit will be 2(x – 1).
If x = 2, then the tens digit is 2 – 1 = 1, and the ones digit is 2 × 1 = 2. So the number is 194.
Thus, the answer is 194!
Question 17: I am a two-digit number. If you subtract my ones digit from my tens digit, you get 5. What number am I?
Answer: The number is 53.
Explanation:
Let the tens digit be x and the ones digit be y. We know x – y = 5. Testing values, we find x = 5 and y = 3, so the number is 53.
Thus, the answer is 53!
Question 18: I am a number between 20 and 30. When I am multiplied by 3, I give a number between 70 and 80. What number am I?
Answer: The number is 24.
Explanation:
When you multiply 24 by 3, you get 72, which lies between 70 and 80.
Thus, the answer is 24!
Question 19: I am a number that when divided by 4, the remainder is 3. What number am I?
Answer: The number is 7.
Explanation:
When 7 is divided by 4, the quotient is 1, and the remainder is 3.
Thus, the answer is 7!
Question 20: What number am I? I am a two-digit number. My ones digit is 4 more than my tens digit, and the sum of my digits is 10.
Answer: The number is 64.
Explanation:
Let the tens digit be x and the ones digit be x + 4.
The sum of the digits is 10, so x + (x + 4) = 10.
Solving for x, we get x = 3, and the number is 64.
Thus, the answer is 64!
Question 21: I am a number that when you reverse my digits, I become twice as large as I originally was. What number am I?
Answer: The number is 12.
Explanation:
Let the number be 10x + y, where x is the tens digit and y is the ones digit.
Reversing the digits gives 10y + x = 2(10x + y).
Solving for x = 1 and y = 2, so the number is 12.
Thus, the answer is 12!
Question 22: What is the next number in the sequence: 1, 2, 6, 24, ?
Answer: The next number is 120.
Explanation:
The pattern is multiplying by consecutive numbers: 1 × 1 = 1, 1 × 2 = 2, 2 × 3 = 6, 6 × 4 = 24, and 24 × 5 = 120.
Thus, the answer is 120!
Question 23: I am a two-digit number. When you reverse my digits, I become 9 more than my original number. What number am I?
Answer: The number is 45.
Explanation:
Let the number be 10x + y, where x is the tens digit and y is the ones digit.
Reversing the digits gives the number 10y + x = 10x + y + 9.
Solving for x = 4 and y = 5, so the number is 45.
Thus, the answer is 45!
Question 24: I am a number between 100 and 200. My tens digit is half of my hundreds digit, and my ones digit is the sum of my tens and hundreds digits. What number am I?
Answer: The number is 132.
Explanation:
Let the hundreds digit be 1, the tens digit is 1/2 = 3, and the ones digit is 1 + 3 = 2.
So the number is 132.
Thus, the answer is 132!
Question 25: I am a number. I am the product of 3 and 5, and I am less than 20. What number am I?
Answer: The number is 15.
Explanation:
The product of 3 and 5 is 15, which is less than 20.
Thus, the answer is 15!
Question 26: I am a three-digit number. My hundreds digit is the sum of my tens and ones digits. What number am I?
Answer: The number is 121.
Explanation:
Let the hundreds digit be x, the tens digit be y, and the ones digit be z.
We know that x = y + z.
If x = 1, y = 2, and z = 1, the number is 121.
Thus, the answer is 121!
Question 27: I am a number. When you subtract 7 from me, the result is a number that is divisible by 5. What number am I?
Answer: The number is 12.
Explanation:
When you subtract 7 from 12, you get 5, which is divisible by 5.
Thus, the answer is 12!
Question 28: What is the next number in the sequence: 5, 10, 20, 40, ?
Answer: The next number is 80.
Explanation:
The pattern is multiplying by 2: 5 × 2 = 10, 10 × 2 = 20, 20 × 2 = 40, and 40 × 2 = 80.
Thus, the answer is 80!
Question 29: I am a number. If you add 8 to me, you get a number whose digits add up to 18. What number am I?
Answer: The number is 27.
Explanation:
When you add 8 to 27, you get 35, and the sum of the digits of 35 is 3 + 5 = 18.
Thus, the answer is 27!
Question 30: I am a number between 10 and 50. I am divisible by 4 and 6. What number am I?
Answer: The number is 24.
Explanation:
The smallest number between 10 and 50 that is divisible by both 4 and 6 is 24.
Thus, the answer is 24!
Question 31: I am a four-digit number. My tens digit is half of my hundreds digit, and my ones digit is three times my tens digit. The sum of all my digits is 19. What number am I?
Answer: The number is 8347.
Explanation:
Let the thousands digit be x, the hundreds digit be y, the tens digit be z, and the ones digit be w.
We are given the following clues:
- “The tens digit is half of my hundreds digit.” So, z = y/2.
- “My ones digit is three times my tens digit.” So, w = 3z.
- “The sum of all my digits is 19.” So, x + y + z + w = 19.
By solving these equations, we get x = 8, y = 6, z = 3, and w = 9, so the number is 8347.
Thus, the answer is 8347!
Question 32: I am a three-digit number. The product of my digits is 72, and the sum of my digits is 15. What number am I?
Answer: The number is 684.
Explanation:
Let the digits be x, y, and z. We know that:
- “The product of my digits is 72.” So, x × y × z = 72.
- “The sum of my digits is 15.” So, x + y + z = 15.
Testing possible combinations that satisfy both equations, we find that the digits are 6, 8, and 4, so the number is 684.
Thus, the answer is 684!
Question 33: I am a three-digit number. My hundreds digit is 1 more than my tens digit, and my ones digit is 3 less than my tens digit. What number am I?
Answer: The number is 532.
Explanation:
Let the tens digit be x, the hundreds digit is x + 1, and the ones digit is x – 3.
Testing values for x, we find that x = 5 satisfies the conditions, so the number is 532.
Thus, the answer is 532!
Question 34: I am a two-digit number. My tens digit is one less than twice my ones digit, and the sum of my digits is 11. What number am I?
Answer: The number is 38.
Explanation:
Let the tens digit be x, and the ones digit be y.
We know that:
- “The tens digit is one less than twice my ones digit.” So, x = 2y – 1.
- “The sum of my digits is 11.” So, x + y = 11.
By solving these equations, we get x = 8 and y = 3, so the number is 38.
Thus, the answer is 38!
Question 35: I am a three-digit number. My ones digit is 2 more than my tens digit, and my hundreds digit is 3 less than my tens digit. The sum of my digits is 12. What number am I?
Answer: The number is 471.
Explanation:
Let the tens digit be x, the ones digit is x + 2, and the hundreds digit is x – 3.
We know that:
- “The sum of my digits is 12.” So, (x – 3) + x + (x + 2) = 12.
Simplifying this equation, we get 3x – 1 = 12, which gives x = 4. Therefore, the number is 471.
Thus, the answer is 471!
Question 36: I am a four-digit number. The sum of my digits is 18, and the product of my digits is 432. What number am I?
Answer: The number is 2346.
Explanation:
Let the digits of the four-digit number be x, y, z, and w.
We know that:
- “The sum of my digits is 18.” So, x + y + z + w = 18.
- “The product of my digits is 432.” So, x × y × z × w = 432.
By solving these equations, we find that x = 2, y = 3, z = 4, and w = 6, so the number is 2346.
Thus, the answer is 2346!
Question 37: I am a number between 1 and 100. When I am divided by 4, I leave a remainder of 3. When I am divided by 5, I leave a remainder of 4. What number am I?
Answer: The number is 39.
Explanation:
We are looking for a number between 1 and 100 that satisfies the following conditions:
- “When divided by 4, I leave a remainder of 3.” This means the number is of the form 4n + 3.
- “When divided by 5, I leave a remainder of 4.” This means the number is of the form 5m + 4.
Testing numbers that satisfy both conditions, we find that 39 satisfies both conditions.
Thus, the answer is 39!
Question 38: I am a two-digit number. The difference between my digits is 4, and the sum of my digits is 10. What number am I?
Answer: The number is 64.
Explanation:
Let the tens digit be x and the ones digit be y.
We are given that:
- “The difference between my digits is 4.” So, x – y = 4.
- “The sum of my digits is 10.” So, x + y = 10.
By solving these equations, we get x = 7 and y = 3, so the number is 64.
Thus, the answer is 64!
Question 39: I am a three-digit number. My tens digit is 4 times my ones digit, and my hundreds digit is 1 less than my tens digit. What number am I?
Answer: The number is 142.
Explanation:
Let the ones digit be x, the tens digit is 4x, and the hundreds digit is 4x – 1.
Testing for valid values of x, we find that when x = 2, the number is 142.
Thus, the answer is 142!
Question 40: I am a four-digit number. My thousands digit is 2 more than my hundreds digit, and my tens digit is 3 more than my ones digit. The sum of my digits is 22. What number am I?
Answer: The number is 5277.
Explanation:
Let the digits of the number be x, y, z, and w for thousands, hundreds, tens, and ones digits, respectively.
We are given:
- “My thousands digit is 2 more than my hundreds digit.” So, x = y + 2.
- “My tens digit is 3 more than my ones digit.” So, z = w + 3.
- “The sum of my digits is 22.” So, x + y + z + w = 22.
By solving these equations, we get x = 5, y = 3, z = 7, and w = 4, so the number is 5277.
Thus, the answer is 5277!
