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Home»Class 8 Study Material: Notes, Solutions & Worksheets»NCERT Solutions for Class 8 Maths Exercise 12.1 Factorisation
Class 8 Study Material: Notes, Solutions & Worksheets

NCERT Solutions for Class 8 Maths Exercise 12.1 Factorisation

Updated:February 9, 20247 Mins Read

In algebra, factors are the building blocks that combine tigether to form expressions. For example, in the term 5xy, the factors are 5, x, and y. We express this as 5xy = 5 * x * y. These factors cannot be broken down further into other factors.

Taking another example, the expression 4x(x + 3) is the product of the irreducible factors 4, x, and (x + 3), written as 4x(x + 3) = 4 * x * (x + 3).

What is Factorisation?

Factorization is the process of breaking down an algebraic expression into its factors. For example, expressions such as 7xz, 9x²z, and 6x(z + 4) are already factorized. Their factors are straightforward.

However, expressions like 2x + 6 or x² + 7x + 12 are not factorized. To factorize them, we must use methods to find their irreducible factors. For 2x + 6, we can factor out a 2, giving us 2(x + 3). For x² + 7x + 12, we find factors (x + 3)(x + 4) that multiply to give the original expression. These methods are important to simplifying algebraic expressions.

NCERT Solutions for Class 8 Maths Exercise 12.2 Chapter 12 Factorisation

1. Find the common factors of the given terms.

(i) 12x, 36 (ii) 2y, 22xy (iii) 14 pq, 28p²q² (iv) 2x, 3x², 4 (v) 6 abc, 24ab², 12 a²b (vi) 16 x³, – 4x², 32x (vii) 10 pq, 20qr, 30rp (viii) 3x² y³, 10x³ y²,6 x² y²z

Finding Common Factors of Given Terms:

(i) Common factors of 12x, 36

Step 1: Identify the prime factors.
12x = 2 * 2 * 3 * x
36 = 2 * 2 * 3 * 3

Step 2: Find common prime factors.
Common factors = 2 * 2 * 3 = 12

(ii) Common factors of 2y, 22xy

Step 1: Identify the prime factors.
2y = 2 * y
22xy = 2 * 11 * x * y

Step 2: Find common prime factors.
Common factors = 2 * y = 2y

(iii) Common factors of 14pq, 28p²q²

Step 1: Identify the prime factors.
14pq = 2 * 7 * p * q
28p²q² = 2 * 2 * 7 * p * p * q * q

Step 2: Find common prime factors.
Common factors = 2 * 7 * p * q = 14pq

(iv) Common factors of 2x, 3x², 4

Step 1: Identify the prime factors.
2x = 2 * x
3x² = 3 * x * x
4 = 2 * 2

Step 2: Find common prime factors.
Common factors = None (No common factors among all three terms)

(v) Common factors of 6abc, 24ab², 12a²b

Step 1: Identify the prime factors.
6abc = 2 * 3 * a * b * c
24ab² = 2 * 2 * 2 * 3 * a * b * b
12a²b = 2 * 2 * 3 * a * a * b

Step 2: Find common prime factors.
Common factors = 2 * 3 * a * b = 6ab

(vi) Common factors of 16 x³, –4x², 32x

Step 1: Identify the prime factors.
16 x³ = 2 * 2 * 2 * 2 * x * x * x
-4x² = 2 * 2 * x * x
32x = 2 * 2 * 2 * 2 * 2 * x

Step 2: Find common prime factors.
Common factors = 2 * 2 * x = 4x

(vii) Common factors of 10pq, 20qr, 30rp

Step 1: Identify the prime factors.
10pq = 2 * 5 * p * q
20qr = 2 * 2 * 5 * q * r
30rp = 2 * 3 * 5 * r * p

Step 2: Find common prime factors.
Common factors = 5 (Only 5 is common among all)

(viii) Common factors of 3x²y³, 10x³y², 6x²y²z

Step 1: Identify the prime factors.
3x²y³ = 3 * x * x * y * y * y
10x³y² = 2 * 5 * x * x * x * y * y
6x²y²z = 2 * 3 * x * x * y * y * z

Step 2: Find common prime factors.

Common factors = x * x * y * y = x²y²

2. Factorise the following expressions.

(i) 7x – 42 (ii) 6p – 12q (iii) 7a² + 14a (iv) – 16 z + 20 z³ (v) 20 l² m + 30 a l m (vi) 5 x² y – 15 xy² (vii) 10 a² – 15 b² + 20 c² (viii) – 4 a² + 4 ab – 4 ca (ix) x² y z + x y²z + x y z² (x) a x² y + b x y² + c x y z

Factorising the Following Expressions:

(i) 7x – 42
Here 7x = 7 * x and 42 = 2 * 3 * 7
Factorise:
7 * x – 2 * 3 * 7
= 7 * (x – 2 * 3)
= 7(x – 6)

(ii) 6p – 12q
Factorise:
6 * p – 6 * 2 * q
= 6(p – 2q)

(iii) 7a² + 14a
Factorise:
7 * a * a + 7 * 2 * a
= 7a(a + 2)

(iv) – 16z + 20z³
Factorise:
-4 * 4 * z + 4 * 5 * z * z * z
= 4z(-4 + 5z²)

(v) 20l²m + 30alm
Factorise:
10 * 2 * l * l * m + 10 * 3 * a * l * m
= 10 * l * m * (2l + 3a)

(vi) 5x²y – 15xy²
Factorise:
5 * x * x * y – 5 * 3 * x * y * y
= 5xy * (x – 3y)

(vii) 10a² – 15b² + 20c²
Factorise:
5 * 2 * a * a – 5 * 3 * b * b + 5 * 4 * c * c
= 5 * (2a² – 3b² + 4c²)

(viii) –4a² + 4ab – 4ca
Factorise:
-4 * a * a + 4 * a * b – 4 * c * a
= 4a * (-a + b – c)

(ix) x²yz + xy²z + xyz²
Factorise:
x * x * y * z + x * y * y * z + x * y * z * z
= xyz * (x + y + z)

(x) ax²y + bxy² + cxyz
Factorise:
x * a * x * y + x * b * y * y + x * c * y * z
= xy * (ax + by + cz)

3. Factorise.

(i) x² + x y + 8x + 8y (ii) 15 xy – 6x + 5y – 2 (iii) ax + bx – ay – by (iv) 15 pq + 15 + 9q + 25p (v) z – 7 + 7 x y – x y z

(i) x² + x y + 8x + 8y
Factorise:
= x * (x + y) + 8 * (x + y)
= (x + y)(x + 8)

(ii) 15 xy – 6x + 5y – 2
Factorise:
= 3x * (5y – 2) + 1 * (5y – 2)
= (5y – 2)(3x + 1)

(iii) ax + bx – ay – by
Factorise:
= a * (x – y) + b * (x – y)
= (x – y)(a + b)

(iv) 15 pq + 15 + 9q + 25p
Factorise:
= 3 * (5pq + 5 + 3q + 25/3 * p)
= 3(5 * (pq + 1) + 3q + 25/3 * p)

(v) z – 7 + 7xy – xyz
Factorise:
= 1 * (z – 7) + xy * (7 – z)
= (z – 7)(1 – xy)

Previous ArticleNCERT Solutions for Class 8 Maths Exercise 6.1 Cubes and Cube Roots
Next Article NCERT Solutions for Class 8 Maths Exercise 12.2 Factorisation
Amit

Amit, a BE in Mechanical Engineering, is a math enthusiast dedicated to making math fun and accessible for kids in classes 1 to 10. With a knack for simplifying complex concepts, Amit offers easy-to-understand solutions, fostering a love for math in young minds across India.

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