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Home»MAT»4th Class Mental Ability Coding-Decoding Question & Answers
MAT

4th Class Mental Ability Coding-Decoding Question & Answers

Updated:March 17, 202610 Mins Read

Practice a wide variety of mental ability test questions on coding–decoding for class 4. Start with easy patterns and level up to very tough multi-step logic. Each answer includes a short explanation.

4th Class Mental Ability Coding-Decoding

Easy Level (15 Questions) Mental Ability Coding-Decoding Question for Class 4

Letter Shift (+1)

Question 1. If CAT = DBU, then DOG = ?

a) EPH
b) DPF
c) EOH
d) FPH

Answer:

a) EPH — Each letter +1: D→E, O→P, G→H.

Word Substitution

Question 2. If ‘Pen’ is called ‘Book’, ‘Book’ is called ‘Paper’, and ‘Paper’ is called ‘Ink’, which is used to write?

a) Ink
b) Book
c) Paper
d) Pen

Answer:

b) Book — We write with a Pen, which is called ‘Book’.

Alphabet Positions

Question 3. Using A=1, B=2, …, Z=26, the code for RISHI is:

a) 18-9-19-8-9
b) 19-18-8-9-19
c) 18-9-8-19-9
d) 18-19-9-8-9

Answer:

a) 18-9-19-8-9 — R(18) I(9) S(19) H(8) I(9).

Reverse Word

Question 4. If FLOWER is written as REWOLF, how is GARDEN written?

a) NEDRAG
b) DENGAR
c) NEDGAR
d) GARDNE

Answer:

a) NEDRAG — Reverse the letters.

Letter Shift (+1)

Question 5. If LION = MJPO, then BEAR = ?

a) CFBS
b) CGAS
c) CFBQ
d) CFBS

Answer:

a) CFBS — +1: B→C, E→F, A→B, R→S.

Sentence Substitution

Question 6. If ‘Sky’ means ‘Ground’, ‘Ground’ means ‘Sea’, and ‘Sea’ means ‘Air’, where do airplanes fly?

a) Ground
b) Air
c) Sky
d) Sea

Answer:

d) Sea — Air is called ‘Sea’.

Sum of Positions

Question 7. APPLE is coded as 50 (sum of letter positions). What is the code for GRAPE?

a) 47
b) 46
c) 52
d) 55

Answer:

a) 47 — 7+18+1+16+5 = 47.

Symbol Mapping

Question 8. If A=★, B=☆, C=♣, D=♠, then BAD is coded as:

a) ☆★♠
b) ★☆♠
c) ☆♠★
d) ♠☆★

Answer:

a) ☆★♠ — B=☆, A=★, D=♠.

Positions

Question 9. ‘MANGO’ is coded as ’13-1-14-7-15′. How is ‘APPLE’ coded?

a) 1-16-16-12-5
b) 1-15-16-12-5
c) 1-16-15-12-5
d) 11-3-19-12-5

Answer:

a) 1-16-16-12-5 — A(1) P(16) P(16) L(12) E(5).

Direct Positions

Question 10. In a code, CLASS is 3-12-1-19-19. How is SCHOOL written?

a) 19-3-8-15-15-12
b) 18-3-8-15-15-12
c) 19-4-8-16-16-12
d) 19-3-7-15-15-12

Answer:

a) 19-3-8-15-15-12 — S C H O O L.

Reverse Letters

Question 11. If SCHOOL → LOOCSH, then GAMES → ?

a) SEMAG
b) SEAMG
c) SGEAM
d) SEMA G

Answer:

a) SEMAG — Reverse the word.

Skip-1 Pick

Question 12. Write every second letter of ELEPHANT starting from the first.

a) EEA
b) ELHT
c) ELPHT
d) EEA T

Answer:

b) ELHT — E(1), L(3), H(5), T(7).

Mirror (Atbash)

Question 13. Using mirror positions (A↔Z, B↔Y, …), the mirror of DOG is:

a) WLT
b) WLR
c) WOL
d) WLV

Answer:

a) WLT — D→W, O→L, G→T.

Count Vowels

Question 14. Code equals number of vowels in the word. For ORANGE, code is:

a) 2
b) 3
c) 4
d) 1

Answer:

b) 3 — O, A, E.

Telephone Keypad

Question 15. Using keypad (ABC=2, DEF=3, GHI=4, JKL=5, MNO=6, PQRS=7, TUV=8, WXYZ=9), code for CAT is:

a) 222
b) 228
c) 248
d) 242

Answer:

b) 228 — C(2) A(2) T(8).


Medium Level (15 Questions) Mental Ability Coding-Decoding Question for Class 4

Letter Shift (-1)

Question 16. If ZEBRA becomes YDAQZ, then LEMON becomes:

a) KDLNM
b) KDKMN
c) KDLNL
d) KDLNM

Answer:

a) KDLNM — Each letter −1.

Odd–Even Pair Swap

Question 17. Swap letters in pairs: COMPUTER → ?

a) OCMPUTRE
b) OCMPUERT
c) OCPMOUTE
d) OCMPOETU

Answer:

a) OCMPUTRE — CO→OC, MP→PM, UT→TU, ER→RE → OC PM TU RE.

Position Difference

Question 18. For two letters XY, code is |pos(X)−pos(Y)|. For HM the code is:

a) 6
b) 5
c) 4
d) 3

Answer:

b) 5 — |8−13| = 5.

Reverse + Shift (+1)

Question 19. Code = reverse the word, then shift each letter +1. For BAT:

a) UBC
b) CBU
c) UCB
d) CBV

Answer:

a) UBC — BAT → TAB → UBC.

Odd-Position Extract

Question 20. Pick letters at odd positions from NOTEBOOK.

a) NTEO
b) NTEOK
c) NTOO
d) NTEK

Answer:

a) NTEO — Positions 1,3,5,7.

Count Consonants

Question 21. Code equals number of consonants. For TIGER, code is:

a) 2
b) 3
c) 4
d) 5

Answer:

b) 3 — T, G, R.

Split & Reverse Halves

Question 22. Split NOTEBOOK into NOTE and BOOK, reverse each, then join.

a) ETONKOOB
b) ETONBOOk
c) ETONKO OB
d) ETO NKOOB

Answer:

a) ETONKOOB.

Word Substitution (Places)

Question 23. If ‘School’ is ‘Garden’, ‘Garden’ is ‘Library’, ‘Library’ is ‘Home’, where do children study?

a) Library
b) Home
c) School
d) Garden

Answer:

a) Library — School→Garden→Library.

Mirror + Reverse

Question 24. Take mirror letters (A↔Z, …) then reverse. Code of CAT is:

a) GZX
b) XZG
c) XZB
d) GXZ

Answer:

a) GZX — C→X, A→Z, T→G → reverse = G Z X.

Sum of Positions

Question 25. Find sum of positions for SCHOOL.

a) 72
b) 73
c) 74
d) 76

Answer:

a) 72 — 19+3+8+15+15+12=72.

Even-Position Shift (+2)

Question 26. For SCHOOL, add +2 to even positions only (positions from 1).

a) S E I Q O N
b) S E I Q O N (spaces optional)
c) S E H Q O N
d) S D I Q O N

Answer:

a) S E I Q O N — 1:S, 2:C→E, 3:H, 4:O→Q, 5:O, 6:L→N.

Letter Shift Pattern (+2, −1, +2, −1, …)

Question 27. Apply +2, −1, +2, −1, … on APPLE.

a) CORKG
b) CORKD
c) BORKG
d) CONKG

Answer:

a) CORKG — A→C, P→O, P→R, L→K, E→G.

Two-Word Positions

Question 28. BOY = 2-15-25 and GIRL = 7-9-18-12. CHILD is:

a) 3-8-9-12-4
b) 3-9-8-12-4
c) 3-8-9-11-4
d) 3-7-9-12-4

Answer:

a) 3-8-9-12-4 — C H I L D.

Sum vs Product

Question 29. For a 3-letter word XYZ, code is (X+Y+Z, X×Y×Z). For CAT the pair is:

a) (24, 60)
b) (23, 60)
c) (24, 45)
d) (25, 60)

Answer:

a) (24, 60) — 3+1+20=24; 3×1×20=60.

Positions (Direct)

Question 30. Code for DOG is:

a) 4-15-7
b) 4-16-7
c) 5-15-7
d) 5-16-7

Answer:

a) 4-15-7 — D O G.


Tough Level (15 Questions) Mental Ability Coding-Decoding Question for Class 4

Alternate Shift (Odd +1, Even −1)

Question 31. Apply: odd positions +1, even positions −1 on TIGER.

a) UHFDS
b) UJFDQ
c) UHFDR
d) UHF DQ

Answer:

a) UHFDS — T→U, I→H, G→H, E→D, R→S.

Reverse Every Pair

Question 32. Reverse each pair of letters in ELEPHANT (EL)(EP)(HA)(NT).

a) LEPEAHNT
b) LEPEAH TN
c) LEPEAHNT (spaces optional)
d) LEEPHA NT

Answer:

a) LEPEAHNT — EL→LE, EP→PE, HA→AH, NT→TN.

Mirror (Whole Word)

Question 33. Mirror code (A↔Z) of BEAR:

a) YVZI
b) YVZI (no spaces)
c) YVZI (same)
d) YWZI

Answer:

a) YVZI — B→Y, E→V, A→Z, R→I.

Reverse + Mirror

Question 34. Reverse word then mirror letters. For LATE:

a) OZIG
b) OZIR
c) OZGV
d) OZGV (same)

Answer:

c) OZGV — LATE→ETAL; E→V, T→G, A→Z, L→O → V G Z O → reversed order from step = OZGV.

Paired-End Sums

Question 35. For LEMON, add L+N and E+O (ignore middle M). Give pair:

a) (26, 20)
b) (25, 20)
c) (26, 19)
d) (27, 20)

Answer:

a) (26, 20) — 12+14=26; 5+15=20.

Index-Weighted Sum

Question 36. Value = Σ[i×pos(letter_i)], i from 1. For CAT:

a) 65
b) 60
c) 63
d) 58

Answer:

a) 65 — 1×3 + 2×1 + 3×20 = 3 + 2 + 60.

Vowel-Next, Consonant-Prev

Question 37. Replace vowels by next vowel (A→E, E→I, I→O, O→U, U→A) and consonants by previous letter. For NOTE:

a) MU SI
b) MUSI
c) NUSI
d) MTSI

Answer:

b) MUSI — N→M, O→U, T→S, E→I.

Extract Even Positions

Question 38. Take letters at even positions of STRAWBERRY.

a) TABRY
b) TRWER
c) TARBY
d) TARRY

Answer:

a) TABRY — Positions 2,4,6,8,10 → T, A, B, R, Y.

Block Shift

Question 39. Split ELEPHANT into ELEP and HANT; shift first block +1 and second block −1.

a) FMFQGZMS
b) FMFQGAMS
c) FMFQHZMS
d) FNFQGZMS

Answer:

a) FMFQGZMS — ELEP→FMFQ; HANT→GZMS.

Positions Sum to Target

Question 40. Which word has sum of positions = 33?

a) BANANA
b) PEACH
c) KIWI
d) PEAR

Answer:

a) BANANA — 2+1+14+1+14+1 = 33.

Double Shift (+1 then +2)

Question 41. Shift first two letters of MINT by +1, remaining by +2.

a) N J P V
b) N J P U
c) NJPV
d) NJPU

Answer:

c) NJPV — M→N, I→J, N→P, T→V.

Mirror at Odd, +1 at Even

Question 42. For TIGER, mirror odd positions, add +1 to even positions.

a) GJTFI
b) GJTFH
c) GHTFI
d) GJTEI

Answer:

a) GJTFI — T→G, I→J, G→T, E→F, R→I.

Sum of First & Last Only

Question 43. For STARS, code = pos(first)+pos(last). What is it?

a) 38
b) 37
c) 39
d) 36

Answer:

a) 38 — S(19)+S(19)=38.

Replace by Previous

Question 44. Replace each letter by the previous one. For MOUSE:

a) L N T R D
b) LNT RD
c) LNTRD
d) LO TRD

Answer:

c) LNTRD — M→L, O→N, U→T, S→R, E→D.

Reverse Middle Only

Question 45. For 5-letter words ABCDE, reverse only BCD. For PLANT:

a) P L A N T (no change)
b) P A L N T
c) P A L N T (same as b)
d) P N L A T

Answer:

b) PALNT — BCD = LAN → reversed = NAL → P N A L T, but positions keep A in middle: P A L N T. (PALNT)


Very Tough Level (5 Questions) Mental Ability Coding-Decoding Question for Class 4

Two-Step Mirror-Shift

Question 46. Take mirror letter (A↔Z) then shift +1. Code for BAG is:

a) ZAU
b) YAU
c) ZAV
d) ZBU

Answer:

a) ZAU — B→Y→Z, A→Z→A, G→T→U → Z A U.

Chain Substitution

Question 47. If ‘Rain’ is ‘Sun’, ‘Sun’ is ‘Cloud’, ‘Cloud’ is ‘Wind’, then what falls from the sky?

a) Sun
b) Cloud
c) Wind
d) Rain

Answer:

a) Sun — Rain falls; Rain is called ‘Sun’.

Three-Step Mix

Question 48. Steps: (i) reverse word, (ii) vowels → next vowel, (iii) consonants −1. For NOTE:

a) ISMU
b) I SMU
c) ISMV
d) ISNU

Answer:

a) ISMU — NOTE→ETON; vowels: E→I, O→U; consonants: T→S, N→M → I S M U.

Index Math

Question 49. Value = Σ[i×pos(letter_i)] for DOG.

a) 55
b) 56
c) 57
d) 58

Answer:

a) 55 — 1×4 + 2×15 + 3×7 = 4 + 30 + 21.

Alternating Mirror

Question 50. For TIGER, mirror odd positions and keep even positions unchanged.

a) G I T E I
b) G I T E R
c) G I T E H
d) G H T E I

Answer:

a) G I T E I — T→G, I→I, G→T, E→E, R→I.

Coding-Decoding Questions for other Classes

  • 4th Class Mental Ability Coding-Decoding
  • 5th Class Mental Ability Coding-Decoding
  • 6th Class Mental Ability Coding-Decoding
  • 7th Class Mental Ability Coding-Decoding
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Amit holds a BE in Mechanical Engineering and brings a genuine passion for mathematics to IndiaFolks. He creates NCERT-aligned content for students from Classes 4 to 10. He specialises in breaking down tricky concepts into clear, step-by-step solutions, from worksheets and MCQs to aptitude problems. He makes the tough problems easier for Indian students to build confidence and score better in Maths. His goal is simple: turn every student into a problem-solver who actually enjoys the subject.

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