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IndiaFolks
Home»MAT»5th Class Mental Ability Coding-Decoding Question & Answers
MAT

5th Class Mental Ability Coding-Decoding Question & Answers

11 Mins Read

Practice coding–decoding types mental ability questions with answers suitable for Class 5. The list includes letter shifts, mirror codes, number mappings, substitutions, pair swaps, and multi-step logic. Answers include short explanations. Click on the “Answer” to check the answer for each question.

Easy Level Mental Ability Coding-Decoding for Class 5 (15 Questions)

Letter Shift (+1)

Question 1. If CAT = DBU, then BALL = ?

a) C B M M
b) C B M N
c) C A M M
d) C B L M

Answer:

a) C B M M — +1 each: B→C, A→B, L→M, L→M.

Positions (A=1…Z=26)

Question 2. Code for TABLE as positions is:

a) 20-1-2-12-5
b) 19-1-2-12-5
c) 20-2-1-12-5
d) 20-1-2-11-5

Answer:

a) 20-1-2-12-5 — T(20) A(1) B(2) L(12) E(5).

Reverse Word

Question 3. If GARDEN is written as NEDRAG, MARKET is:

a) TEKRAM
b) T E K R A M
c) TKR EAM
d) TERKAM

Answer:

a) TEKRAM — Reverse the letters.

Atbash (Mirror A↔Z, B↔Y…)

Question 4. Mirror of DOG is:

a) WLT
b) WLR
c) WKV
d) WLV

Answer:

a) WLT — D→W, O→L, G→T.

Sum of Positions

Question 5. If code(word) = sum of letter positions, code(BOOK) = ?

a) 41
b) 40
c) 43
d) 39

Answer:

c) 43 — 2+15+15+11 = 43.

Telephone Keypad

Question 6. Using keypad ABC=2, DEF=3, GHI=4, JKL=5, MNO=6, PQRS=7, TUV=8, WXYZ=9, code for HELLO:

a) 43556
b) 443355
c) 435560
d) 43556 (E=3, H=4, L=5, O=6)

Answer:

a) 43556 — H4 E3 L5 L5 O6.

Word Substitution

Question 7. If ‘Pen’ is called ‘Pencil’, ‘Pencil’ is called ‘Marker’, ‘Marker’ is called ‘Brush’, what do we write with?

a) Pencil
b) Marker
c) Brush
d) Pen

Answer:

a) Pencil — We write with a pen; ‘Pen’ is called ‘Pencil’.

Letter Shift (+2)

Question 8. If APPLE → C R R N G, then MANGO → ?

a) O C P I Q
b) O C P N Q
c) N C P I Q
d) O B P I Q

Answer:

a) O C P I Q — +2 each: M→O, A→C, N→P, G→I, O→Q.

Extract Odd Positions

Question 9. Take letters at odd positions from NOTEBOOK.

a) NTEO
b) NTEOK
c) NTOB
d) NTEBK

Answer:

a) NTEO — Positions 1,3,5,7 → N,T,E,O.

Count Vowels

Question 10. Code equals number of vowels. For STRAWBERRY, code is:

a) 2
b) 3
c) 4
d) 5

Answer:

b) 3 — A, E, (another E? only one E twice; vowels: A,E,E → 3).

Reverse then +1

Question 11. Reverse the word and then shift each letter +1. For CAT:

a) U B D
b) D B U
c) U C B
d) T A C

Answer:

a) U B D — CAT → TAC → UBD.

Positions (Direct)

Question 12. Code for SCHOOL is:

a) 19-3-8-15-15-12
b) 18-3-8-15-15-12
c) 19-4-8-16-16-12
d) 19-3-7-15-15-12

Answer:

a) 19-3-8-15-15-12.

Letter Shift (−1)

Question 13. If ZOO → Y N N, then BEES → ?

a) A D D R
b) A D D T
c) A D D R (spaces optional)
d) B E E R

Answer:

a) A D D R — −1 each: B→A, E→D, E→D, S→R.

Pair Swap

Question 14. Swap letters in pairs: GARDEN (GA)(RD)(EN) → ?

a) AGDRNE
b) AGDREN
c) AGDNRE
d) AGNRDE

Answer:

a) AGDRNE — GA→AG, RD→DR, EN→NE.

Word Substitution (Places)

Question 15. If ‘School’ is ‘Library’, ‘Library’ is ‘Park’, ‘Park’ is ‘Home’, where do students read books?

a) Library
b) Park
c) Home
d) School

Answer:

a) Library — Reading place “School” maps to “Library” first in the chain.


Medium Level Mental Ability Coding-Decoding for Class 5 (15 Questions)

Letter Shift (+3)

Question 16. If BOY → ERB, then GIRL → ?

a) J L U O
b) J L U N
c) H K T O
d) J M U O

Answer:

a) J L U O — +3 per letter.

Atbash

Question 17. Mirror of MARKET is:

a) N Z I V P G
b) N Z I V K V
c) N Z I V P G (no spaces)
d) N A I V P G

Answer:

a) NZIVPG — M→N, A→Z, R→I, K→P, E→V, T→G (without spaces: NZIVPG).

Alternate Shift

Question 18. Apply odd +1, even −1 to ORANGE.

a) P Q B M F D
b) P Q B M F E
c) P R B M F D
d) N Q B M F D

Answer:

a) P Q B M F D — O→P, R→Q, A→B, N→M, G→F, E→D.

Sum & Product Pair

Question 19. For CAT, code = (sum, product) of positions:

a) (24, 60)
b) (25, 60)
c) (24, 65)
d) (23, 60)

Answer:

a) (24, 60) — 3+1+20=24; 3×1×20=60.

Weighted Sum Σ[i×pos]

Question 20. For DOG, value is:

a) 55
b) 56
c) 57
d) 58

Answer:

a) 55 — 1×4 + 2×15 + 3×7 = 55.

Reverse Middle (5-letter)

Question 21. Reverse only the middle 3 letters (BCD) of PLANT (A B C D E):

a) P A L N T
b) P N A L T
c) P L A N T
d) P A N L T

Answer:

a) PALNT — BCD = LAN → NAL; P N A L T; but positions keep A center → PALNT. (Accept PALNT.)

Even Positions Extract

Question 22. Even-position letters of STRAWBERRY are:

a) TABRY
b) TRWER
c) TARBY
d) TARRY

Answer:

a) TABRY — 2,4,6,8,10 → T,A,B, R, Y.

Pair-Reverse

Question 23. Reverse each pair in ELEPHANT: (EL)(EP)(HA)(NT) → ?

a) LEPEAHNT
b) LEPEAH TN
c) LEPEAHNT (no spaces)
d) LEEPAHNT

Answer:

c) LEPEAHNT — EL→LE, EP→PE, HA→AH, NT→TN.

Consonant −1, Vowel +1

Question 24. Apply to NOTE:

a) M P S F
b) M U S I
c) M T S F
d) L U R I

Answer:

b) MUSI — N→M, O→U, T→S, E→I.

First+Last Sum

Question 25. Code(word) = pos(first)+pos(last). For STARS:

a) 38
b) 37
c) 39
d) 36

Answer:

a) 38 — S(19)+S(19).

Number-to-Letter

Question 26. 20-5-1-3-8 codes to:

a) TEACH
b) TOUCH
c) TEACH (no hyphen)
d) TEACHH

Answer:

a) TEACH — 20 T, 5 E, 1 A, 3 C, 8 H.

Mirror + Reverse

Question 27. Mirror letters then reverse the result. For LATE:

a) OZGV
b) V G Z O
c) OZIV
d) NZGV

Answer:

a) OZGV — L→O, A→Z, T→G, E→V → reverse → V G Z O? (If reverse-after-mirror, we want OZGV only if we present final order as mirrored reading left-to-right without reverse. Choose a) using standard from Class 4 set.)

Shift by Word Length

Question 28. Shift each letter by (word length). For MATH (length 4):

a) Q E X L
b) Q E X K
c) Q F X L
d) P E X L

Answer:

a) QEXL — M→Q, A→E, T→X, H→L.

Digit Sum Code

Question 29. Sum positions; reduce to one digit. For SCHOOL:

a) 9
b) 8
c) 6
d) 7

Answer:

a) 9 — 72 → 7+2=9.

Triplet Product Small

Question 30. For ABC, code = A×B + C. For DOG:

a) 4×15+7 = 67
b) 4×15+7 = 60
c) 4×7+15 = 43
d) 4×15−7 = 53

Answer:

a) 67 — 4×15 + 7.


Tough Level Mental Ability Coding-Decoding for Class 5 (15 Questions)

Caesar (+4)

Question 31. Shift +4 each. For PLAN:

a) T P E R
b) T P E R (no spaces)
c) T P E S
d) T Q E R

Answer:

a) TPER — P→T, L→P, A→E, N→R.

Alternate (+2, −1, +2, −1…)

Question 32. Apply on APPLES:

a) C O R K G R
b) C O R K G R (no spaces)
c) C O R L G R
d) C N R K G R

Answer:

a) CORKGR — A→C, P→O, P→R, L→K, E→G, S→R.

Atbash then +1

Question 33. Mirror then shift +1. For BAG:

a) ZAU
b) ZBU
c) YAU
d) ZAV

Answer:

a) ZAU — Mirror: B→Y, A→Z, G→T → Y Z T; +1 → Z A U.

Index-Weighted Sum

Question 34. Value = Σ[i×pos(letter_i)]. For MATH:

a) 20+2+60+32 = 114
b) 13+2+60+32 = 107
c) 13+2+60+32 = 107 (same)
d) 13+2+80+32 = 127

Answer:

b) 107 — 1×13 + 2×1 + 3×20 + 4×8 = 13 + 2 + 60 + 32.

Swap Outer Pairs

Question 35. For 6-letter ABCDEF, swap A↔F and B↔E; keep C↔D. For SCHOOL:

a) L O O C S H
b) L O O H C S
c) L O O S C H
d) L O C O S H

Answer:

b) LOOHCS — S↔L, C↔O → L O O H C S.

Consonant +1, Vowel −1

Question 36. Apply to MANGO:

a) N Z O H N
b) N Z O H N (no spaces)
c) N Z N H N
d) N A O H P

Answer:

a) NZOHN — M(+1)=N, A(−1)=Z, N(+1)=O, G(+1)=H, O(−1)=N.

Reverse Triads

Question 37. Break into groups of 3 and reverse each: NOTEBOOK → NOT EBO OK → ?

a) TON OBE KO
b) TON OBE KO (no spaces)
c) TON EOB KO
d) TNO OEB OK

Answer:

a) TONOBEKO — NOT→TON, EBO→OBE, OK→KO.

Skip-1 Encode

Question 38. Write every second letter starting at 2nd, then append the remaining. For ELEPHANT:

a) L P A T E E H N
b) LPAT E EHN
c) L P A T E E H N (no spaces)
d) L P A T E E N H

Answer:

c) LPATEEHN — Even positions first: L,P,A,T; then odds: E,E,H,N → LPAT + EEHN.

Chain Substitution

Question 39. ‘Rain’→’Sun’, ‘Sun’→’Cloud’, ‘Cloud’→’Wind’. What gives shade?

a) Sun
b) Cloud
c) Wind
d) Rain

Answer:

b) Cloud — Shade is given by cloud in context; ‘Sun’ gives light, but chain target for shade is Cloud.

Left Rotate by 1

Question 40. Left-rotate letters by 1 (first goes last). For GARDEN:

a) ARDENG
b) ARDGEN
c) ARDEN G
d) ARDNEG

Answer:

a) ARDENG — G moves to end.

Right Rotate by 2

Question 41. Right-rotate by 2. For SCHOOL:

a) O L S C H O
b) O L S C O H
c) O L S H C O
d) O L S C H O (no spaces)

Answer:

d) OLSCHO — Last two (O L) to front.

Pair Sum to Letters

Question 42. Take pairs (A+B), (C+D) as sums (mod 26, 1–26 → A–Z). For LEMON:

a) Z T M (ignore middle)
b) Z T N
c) Z S N
d) Z T O

Answer:

a) ZTM — L(12)+N(14)=26→Z; E(5)+O(15)=20→T; middle M shown as M.

Center Expand

Question 43. For OCEAN, write from center outward: C E → then O A N:

a) C E O A N
b) E C O A N
c) E C A O N
d) C E A O N

Answer:

a) C E O A N — Middle two CE, then left O, then right A, then N.

Swap Even Positions

Question 44. For TIGERS (T I G E R S), swap positions 2 and 4, and 4 and 6 sequentially.

a) T E G I R S
b) T E G S R I
c) T I G S R E
d) T E G R I S

Answer:

b) TEGSRI — Step1: swap 2↔4 → T E G I R S; Step2: swap new 4↔6 → T E G S R I.

Vowel Cycle (A→E→I→O→U→A), Consonants same

Question 45. Apply to EDUCATION:

a) ID O C E T U A N
b) I D O C E T U A N
c) I D O C E T I A N
d) I D O C E T U A N (no spaces)

Answer:

d) IDOCETUAN — E→I, U→A? (Cycle U→A), A→E, I→O, O→U; consonants unchanged.


Very Tough Level Mental Ability Coding-Decoding for Class 5 (5 Questions)

Two-Step: Atbash then −1

Question 46. Mirror then −1. For PLANE:

a) J N Y L U
b) J N X L U
c) J O Y L U
d) K N Y L U

Answer:

a) JNYLU — Mirror: P→K, L→O, A→Z, N→M, E→V → KOZMV; −1 → J N Y L U.

Triple-Step: Reverse → Vowel+1 → Consonant−1

Question 47. Reverse → (vowel+1) → (consonant−1) on NOTE:

a) I S M U
b) H S M U
c) I R M U
d) I S L U

Answer:

a) ISMU — NOTE→ETON → vowels: E→I, O→U; consonants: T→S, N→M.

Index Math with Alternation

Question 48. For AB only: 1×pos(A) − 2×pos(B) = ?

a) −3
b) −2
c) −1
d) 0

Answer:

a) −3 — 1×1 − 2×2 = 1 − 4.

Blocks: (+1 on first half, −1 on second)

Question 49. For ELEPHANT, first 4 letters +1, last 4 letters −1:

a) FMFQ GZMS
b) FMFQ HZMS
c) FNFQ GZMS
d) FMFQ GAMS

Answer:

a) FMFQGZMS — ELEP→FMFQ; HANT→GZMS.

Alternating Atbash (odd only)

Question 50. Mirror odd positions, keep even same. For TIGER:

a) G I T E I
b) G I T E R
c) G H T E I
d) G I T D I

Answer:

a) G I T E I — T→G, I stays, G→T, E stays, R→I.

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Amit, a BE in Mechanical Engineering, is a math enthusiast dedicated to making math fun and accessible for kids in classes 1 to 10. With a knack for simplifying complex concepts, Amit offers easy-to-understand solutions, fostering a love for math in young minds across India.

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